Here a working piece of code :
def test_sqlformgrid():
form = SQLFORM.grid(db.TABLE, ui='jquery-ui',
editable=auth.has_membership('reviewer'),
deletable=auth.has_membership('reviewer'), formstyle = 'divs')
if 'new' in request.args:
if form.create_form
for i in range(0,len(form.create_form[0])):
if len(form.create_form[0][i][2][0]) > 0:
form.create_form[0][i][0].append(SPAN((helpicon(),
SPAN(form.create_form[0][i][2][0])),_class='tooltip'))
del(form.create_form[0][i][2])
return dict(form=form)
Off course the for i in range... Is specific to my need but it the way to
manipulate the generated html form before it goes in user hand...
:)
Richard
On Thu, Nov 10, 2011 at 2:44 PM, Richard Vézina <[email protected]
> wrote:
> It was working "if form.create_form:"...
>
> I thought that grid use form variable doesn't matter if the SQLFORM.grid
> wasn't in a form variable at all...
>
> And my bad because I show form = crud... But it was not my SQLFORM.grid...
> Arrg.
>
> Sorry about that...
>
> Richard
>
> On Thu, Nov 10, 2011 at 1:26 PM, Anthony <[email protected]> wrote:
>
>> On Thursday, November 10, 2011 12:42:49 PM UTC-5, Richard wrote:
>>>
>>>
>>> "if 'new' in request.args:" works (allow to load the grid) but the "if
>>> form.create_form:" not work alone or in conjunction with the former
>>>
>>
>> Yeah, looks like it would have to be something like "if hasattr(form,
>> 'create_form'):".
>>
>
>
