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Instead, though, you might want to explicitly link the two tables:
db.define_table('t_ab_distribution',
Field('f_distributionname'),
format='%(f_distributionname)')
db.define_table('t_ab_recipient',
Field('f_distribution', db.t_ab_distribution))
That will automatically add an IS_IN_DB validator to f_distribution, and it
will display the f_distributionname in the list due to the
format='%(f_distributionname)'.
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Can you do the same with SQLFORM.factory?
I consider that SQLFORM.factory creates a virtual table.
