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2011/12/4 Rick <[email protected]> > I tried to apply the solution to my code, but it still doesn't work. > Here is the code: > > prerecords = db().select(db.day.ALL, orderby=db.day.thedate) for > prerecord in prerecords: if > prerecord.theauth==auth.user_id: if > session.adate==prerecord.thedate: > records.append(prerecord) rows = > select(records.thedate,records.value.sum(),orderby=records.thedate) > for row in rows: print row.records.thedate, > row(records.value.sum()) > On Dec 5, 3:04 am, Massimo Di Pierro <[email protected]> > wrote: > > rows = > > db(...).select(db.table.date,db.table.value.sum(),groupby=db.table.date) > > for row in rows: print row.table.date, row(db.table.value.sum()) > > > > mind that 'date' and 'value' are not good field names. Will work with > > sqlite but will break with other engines. > > > > On Dec 4, 8:00 pm, Rick <[email protected]> wrote: > > > > > > > > > > > > > > > > > Hi, > > > I've a stack of records where records with the same date has different > > > values, eg: > > > record.date[0] = 2011-12-01 > > > record.value[0] = 10 > > > record.date[1] = 2011-12-01 > > > record.value[1] = 20 > > > record.date[3] = 2011-12-02 > > > record.value[3] = 10 > > > And now I want to summarize the values that are recorded for > > > respective date: > > > sumlist.date[0] = 2011-12-01 > > > sumlist.value[0] = 30 > > > sumlist.date[1] = 2011-12-02 > > > sumlist.value[1] = 10 > > > > > I suppose I should use "filter" and "sum", but I don't know how. Any > > > ideas? > > > > > Thanks in advance for help! > -- http://martin.tecnodoc.com.ar
