Thanks Anthony-
On Dec 21, 3:00 pm, Anthony <[email protected]> wrote: > It's tricky, but everything you need is in the encoded filename. With > uploadseparate=True, the file is stored in a subfolder named > /table.field/[first 2 characters of filename uuid]. Try something like this: > > sub = file.split('.') > url = URL('static', 'userpics/%s.%s/%s/%s' % (sub[0], sub[1], sub[2][:2], > file) ) > > Anthony > > > > > > > > On Wednesday, December 21, 2011 2:29:15 PM UTC-5, Yarin wrote: > > > I was trying trying to bypass the download function and use a static > > link > > > According to Massimo: > > "In 'uploads' if you need authorization. In 'static' if you do not. In > > the latter you do not need to worry about > > authorization and you can let the web server by-pass web2py" > > > I actually think the download link will work for me in this case, but > > was wondering how it could be done for static links. > > > On Dec 21, 1:18 pm, Adi <[email protected]> wrote: > > > wouldn't this bring exactly the path where you store it: > > > <div id="image-div"><img src="{{=URL('download', args=image.file)}}" > > > width="100px" alt="some text" /></div> > > > > maybe i'm missing the mark?
