That's it - thank you! 2012/1/3 Alan Etkin <[email protected]>
> I tried the code but changed the import path with this: > > from applications.<app name>.modules.mymodule import ff > > This way the action works. I don't like the fact that the actual app > name has to be passed anyway. A workaround would to use interpolation > and the request.application variable. > > Still, i don't find a way to measure the function code from the same > controller, as in your first post > > On 3 ene, 12:44, Martin Weissenboeck <[email protected]> wrote: > > Now I have tried: > > > > from mymodule import ff > > > > def ff2(): > > return dict(a=ff()) > > > > def tm(): > > import timeit > > t1 = timeit.Timer(stmt='a=2*3').timeit(number=100)/100 > > t2 = timeit.Timer(stmt='a=ff()', > > setup='from mymodule import ff').timeit(number=100)/100 > > return dict(t1=t1, t2=t2) > > > > ff2 is ok, but tm gives > > <type 'exceptions.ImportError'> No module named mymodule > > > > 2012/1/3 Alan Etkin <[email protected]> > > > > > I think that there is a problem with importing functions inside > > > controllers "directly". You could place the function in a module (i.e > > > in modules/mymodule.py and do from mymodule import ff) > > > > > On 3 ene, 05:07, Martin Weissenboeck <[email protected]> wrote: > > > > Hi, > > > > I want to measure some times. > > > > > > My code: > > > > > > def ff(): > > > > return 2*3 > > > > > > def tm(): > > > > import timeit > > > > t1 = timeit.Timer(stmt='a=2*3').timeit(number=100)/100 > > > > t2 = timeit.Timer(stmt='a=ff()',setup='from __main__ import > > > > ff').timeit(number=100)/100 > > > > return dict(t1=t1, t2=t2) > > > > > > t1 is ok, but t2 gives an error: ImportError: cannot import name ff > > > > I understand, that __main__ is not a good idea, but what would be the > > > > correct name? > > > > > > Regards, Martin > > > > >
