Running 1.99.4
I have not been able to get the IS_IN_SET validator to work properly.
I don't know why this should be.
When used with SQLFORM to edit a record, the select field refuses to
show the current value of the field. Instead it shows the first value
in the list or the zero value for the field.
So I made an alternative widget. The code consists of two functions,
below.
If you are having similar problems, feel free to use it.
The _style definition at the end of the call is there to make sure I
was seeing my widget instead of the default. It is not necessary for
the widget to work.
############################################################
def is_it_selected(current_value, option, multiple):
if len(current_value) == 1 or not multiple:
current_value=current_value[0]
if current_value==option:
out = 'selected'
else:
out = None
else:
if option in current_value:
out='selected'
else:
out=None
return out
def my_select_widget(field,value):
# diagnostics uncomment to learn
#print 'value'
#print value
#print 'type(value)'
#print type(value)
f = str(field)
f_name = f.split('.')[-1]
f_id = f.replace('.', '_')
f_requires = db[request.controller][f_name].requires
the_set = f_requires.theset
the_multiple = f_requires.multiple
option_set = []
for t in the_set:
is_selected = is_it_selected(value, t, the_multiple)
option_set.append(OPTION(t, _selected = is_selected))
return SELECT(option_set, _name='status', _id='buckslips_status',
_style='color:red;'
)
