I don't know why you have two {{pass}} in your view. I think you can do:
def jobs():
images=db().select(db.ref.id,db.ref.file)
form = SQLFORM(db.ref)
if form.process().accepted:
response.flash = "Image uploaded"
return dict(form=form, images=images)
in views:
{{for img in images:}}
<image><img width="85px"
src="{{=URL('download', args=img.file)}}" /><br></image>
<br><br><br><br><br>
{{=img}}
{{=img.id}}
{{=form}}
{{pass}}
2012/3/11 juvi1 <[email protected]>
> Hello sorry my bad english and i hope that you understand my problem.
>
> I want show in one page all pictures which are saved in database.
> In page i want that i can upload new picture and update it whit forms
> (override old one)
> My code are
>
> in controller:
> def jobs():
> images=db().select(db.ref.id,db.ref.file)
> for img in images:
> formname = "upload_f_%s"%img.id
> form = FORM(INPUT(_type="file",_name=formname),
> INPUT(_type='submit'))
>
> if form.accepts(request.vars, _name=formname):
> response.flash = form.vars
>
> return dict(form=form, img=img, formname=formname, images=images)
>
> in views:
> {{for img in images:}}
> <image><img width="85px"
> src="{{=URL('download', args=img.file)}}" /><br></image>
> <br><br><br><br><br>
> {{=img}}
> {{formname=img.id}}
> {{=formname}}
> {{=form}}
> {{pass}}{{pass}}
>
> please help!
>
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