Thank you Anthony, you helped me for the first step.
I found the SQLFORM.factory concept and together with your info, I've been
able to get my file and start to process it.
Now, here is how my action looks like:
@auth.requires_login()
def dbimport():
result = "Please, upload a packed database"
form = SQLFORM.factory(Field('packed_db', 'upload', label=T('Packed
database to load'), uploadfolder='uploads'))
if form.process().accepted:
response.flash = 'Machin chargé'
result = packed_db_process(request.vars.packed_db.file)
elif form.errors:
response.flash = 'Pwët error'
return dict(form=form, result=result)
Note that the file does not appear in the uploads folder! That's the reason
why I first was disappointed. But the file is still in memory!
Now that I'm able to process my file (with the zipfile module) I'm able to
extract the csv and the pictures from it, but I need a function to encode
the names from "product 0001.jpg" to
"t_product.f_photo.xxxxxxxxxx.yyyyyyyy.jpg" and store them into the uploads
directory.
Ho, ho ! I think I just found a way there:
http://web2py.com/books/default/chapter/29/6#Manual-uploads
I'll keep you in touch if I get stuck again.
Thank you!
Le Mogwaï
Le jeudi 22 mars 2012 16:00:25 UTC+1, Anthony a écrit :
>
> Upon submission of the form, you should find the file itself in
> request.vars.f_photo.file (and the filename in
> request.vars.f_photo.filename).
>
> Anthony
>
