a = Storage(....) b = Storage(....) a.update(b) should work, a storage is a dict and has a dict.update method.
On Wednesday, 4 April 2012 20:11:12 UTC-5, pbreit wrote: > > Is there an easy way to conjoin two Storage objects (or dicts) together > based on matching keys in each? > > I have the results of two queries and I'd like to combine the sets into > one. Of course I should probably creating a query that does that but I > haven't. I'm also contemplating some NoSQL approaches. >
