I'm having difficulty with this. Here is my code:
def barPlot(data):
from matplotlib.backends.backend_agg import FigureCanvasAgg as
FigureCanvas
from matplotlib.figure import Figure
import cStringIO
stream = cStringIO.StringIO()
cx = data.keys()
cy = data.values()
print cy
fig = Figure()
canvas = FigureCanvas(fig)
ax = fig.add_subplot(1,1,1)
ax.plot(cx, cy)
ax.set_title('hi mom')
ax.grid(True)
ax.set_xlabel('time')
ax.set_ylabel('volts')
canvas.print_png(stream)
return stream.getvalue()
cx is a list of dates, cy is a list of numbers
the function is being called using:
barChart = barPlot(barData)
return dict(fr=fullrange, bc=IMG(_src=URL('barChart'+'.png')))
and my view page code is as follows:
{{extend 'layout.html'}}
<!-- {{=BEAUTIFY(response._vars)}} -->
{{=bc}}
I'm constantly winding up with no image, but it's pointing to barchart.png,
which does not seem to exist.
On Monday, January 16, 2012 2:33:19 PM UTC-5, Massimo Di Pierro wrote:
def image():
> return myimage()
>
> myimage returns the binary data of the image. so calling image would
> be the same as calling myimage. The former never calls the view.
>
> Massimo
>
> On Jan 16, 5:44 am, andrej burja <[email protected]> wrote:
> > this works
> > controller:
> > def image():
> > return dict(a=IMG(_src=URL('myimage'+'.png')))
> > view:
> > {{extend 'layout.html'}}
> > <h1>This is the graph/image.html template</h1>
> > {{=a}}
> >
> > but this doesn't
> > controller:
> > def image():
> > return myimage()
> > view:
> > {{extend 'layout.html'}}
> > <h1>This is the graph/slika1.html template</h1>
> > {{=IMG(_src=URL('myimage'+'.png'))}}
