omg, that is so totally working. cool.
i am almost there. i added this at the top of my function
if ((request.vars._formname<>None) and
(request.vars._formname.rfind('opinion_')>-1)):
f = SQLFORM(db.lecture_item_opinions)
f.vars.lecture_id=lecture.id
f.vars.lecture_item_id=request.vars._formname.rsplit('_')[1]
f.vars.user_id=auth.user_id
if f.process(formname=request.vars._formname).accepted:
session.flash = 'Thank you for your opinion
'+request.vars._formname
elif f.process(formname=request.vars._formname).errors:
response.flash = 'errors'
and it is inserting the data into the postgresql table. great. but the
form is displaying the standard "Success!" and not the one i have above.
how come? i also tried it without an arguement in process.
On Monday, May 14, 2012 10:32:25 PM UTC-4, Anthony wrote:
>
> It's not the variable referring to the form that needs to be unique (you
> can simply append the forms together using CAT() or inside a DIV) --
> rather, each form has a name stored in a hidden _formname field. It is set
> by specifying the "formname" argument to .accepts() or .processs().
>
> f = SQLFORM(db.opinions)
> [more code]
> f.process(formname='myform_%s' % i.id)
>
> When you create the forms, you can do so in a loop and append them all
> together. However, when a specific form is submitted, you don't want to
> create and process all the forms again because you only need to create and
> process the submitted form. So, check for request.vars._formname, and if
> present, just create and process that one form (use the value in
> request.vars._formname to set the "formname" argument in the call to
> .process()).
>
