Maybe something like:
{{for i, s in enumerate(socialmedia):}}
{{if not i % 2:}}<div class="row-fluid">{{pass}}
<div class="span6">{{=s}}</div>
{{if i % 2:}}</div><!-- /row -->{{pass}}
{{pass}}
Anthony
On Friday, June 1, 2012 3:05:00 AM UTC-4, Annet wrote:
>
> In a view I have the following code to generate an ul:
>
> <ul>
> {{for s in socialmedia:}}
> <li>
> </li>
> {{pass}}
> </ul>
>
> I use css to display two list items next to each other. To drop this css
> I'd like to replace this with bootstrap rows:
>
> <div class="row-fluid">
> <div class="span6">
> </div> <!-- /span -->
> <div class="span6">
> </div> <!-- /span -->
> </div> <!-- /row -->
> <div class="row-fluid">
> <div class="span6">
> </div> <!-- /span -->
> <div class="span6">
> </div> <!-- /span -->
> </div> <!-- /row -->
>
> I think the solution lies in doing something with odd and even rows in
> socialmedia. In case of even do:
>
> <div class="row-fluid">
> <div class="span6">
> {{=s.}}
> </div> <!-- /span -->
>
> In case of odd do:
>
> <div class="span6">
> {{=s.}}
> </div> <!-- /span -->
> </div> <!-- /row -->
>
> The problem is I don't know how to establish whether a row is odd or even,
> and how to close the last row in case socialmedia contains an odd number of
> rows.
>
>
> Kind regards,
>
> Annet.
>
>
