You can also do:
response.site_submenu += [list, of, items]
Anthony
On Wednesday, June 20, 2012 3:48:46 AM UTC-4, Niphlod wrote:
>
> did you know about extend ?
>
> >>> mylist = []
> >>> mylist.append(1)
> >>> mylist
> [1]
> >>> mylist.append(2,3)
> Traceback (most recent call last):
> File "<stdin>", line 1, in <module>
> TypeError: append() takes exactly one argument (2 given)
> >>> mylist.extend(2,3)
> Traceback (most recent call last):
> File "<stdin>", line 1, in <module>
> TypeError: extend() takes exactly one argument (2 given)
> >>> mylist.extend([2,3])
> >>> mylist
> [1, 2, 3]
>
>
>
>
> On Wednesday, June 20, 2012 8:03:41 AM UTC+2, Annet wrote:
>>
>> In a controller I have the following menu:
>>
>> response.site_submenu = []
>> if session.vcardsettings:
>> response.site_submenu.append(
>> ['Logo',request.function=='uploadLogo',URL('uploadLogo')],
>> ['Tagline',request.function=='tagline',URL('tagline')],
>> ['Note',request.function=='note',URL('note')])
>> elif session.sitesettings:
>> ...
>>
>> response.site_submenu.append(['Custom_theme',request.function=='customTheme',URL('customTheme')])
>>
>> This results in an error because .append() takes one argument not three.
>> Appending each menu item in a separate .append() solves the problem, but I
>> wonder whether there is another way to solve it>
>>
>> Kind regards,
>>
>> Annet
>>
>
--
