Attachments take an optional parameter to specify the filename, so what is
your current problem ?
You have the original name on the table, you have the path on the table,
you have the file in the uploads directory. Seems to me that you don't have
to copy anything around....
mail.send('[email protected]',
'Message subject',
'Message body',
attachments = [Mail.Attachment('/path/to/fist.file', filename=
"myfilename.jpg"),
Mail.Attachment('/path/to/second.file', filename=
"myfilename2.zip")])
On Friday, August 17, 2012 2:35:38 PM UTC+2, Cliff Kachinske wrote:
>
> How can I email uploaded files with the original file name?
>
> I realize it is possible to make a copy of the file with the original name
> and attach that, but that seems like a waste of resources.
>
> Is there a better way?
>
> thanks,
> Cliff Kachinske
>
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