Hi Andrej
This is something I've also struggled with in all kinds of ways and I'd be
interested in any other replies.
Here is a way I found to count the frequency of a single integer tag.
rows=db().select(db.mytable.tag)
from collections import defaultdict
d = defaultdict(int)
for r in rows:
d[r.tag] += 1
print d
Here is a way of counting the frequency of a list:integer:
rows=db().select(db.mytable.cat).as_list()
res = []
for r in rows:
for i in r.itervalues():
if i: res.extend(i)
from collections import defaultdict
d = defaultdict(int)
for r in sorted(res):
d[r] += 1
print d
Once you have a dict of {id:frequency} I found the rest is easy.
However, I also feel sure there must be an easier way than I have found
above.
Regards, D
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