Thanks for the response guys! I'm going with rochabruno's method as it is the most straightfoward, I hadn't really looked into the compute capabilities.
On Tuesday, September 11, 2012 3:55:21 PM UTC-7, rochacbruno wrote: > > The computation should be > > compute= lambda row: "%(username)s-%(songname)s-%(playlist_name)s" % row > --
