Hi there,
On 16/11/2005, at 10:48 AM, Randy Becker wrote:
On Nov 15, 2005, at 6:21 PM, Sacha Michel Mallais wrote:
On Nov 15, 2005, at 2:46 PM, Randy Becker wrote:
but I'd like to do something like
String format = "(title caseInsensitiveLike %s) OR (title
caseInsensitiveLike %s)";
That exact format string will work. The only difference is you'll
need to include a second argument for the second %s.
by the way, there must be a better way of doing this than the
following:
NSMutableArray arguments = new NSMutableArray();
arguments.addObject(searchQueryWithWildcard);
arguments.addObject(searchQueryWithWildcard);
NSArray args = new NSArray(arguments);
Yep, get rid of the last line; it's redundant as NSMutableArray is an
NSArray.
The options:
1) NSArray args = new NSArray(new Object[] {
o1, o2, ..., oN
});
2) NSMutableArray args = new NSMutableArray();
args.addObject(o1);
args.addObject(o2);
...
args.addObject(oN);
Secondly, how can I display data from an object related to one
that is displayed in a WORepetition. Right now, I'm only able to
access the attributes of a particular object I'm outputting, and
the information I'd like to display is located in a related object.
Through the magic of Key Value Coding. If you have two objects a
and b, where a relates to b, and where both have a "name"
attribute, then all the following will work:
key path gives
----------------------------------------
a the object a
a.name a's name
a.name.length a's name's length
a.b the b that is related to a
a.b.name the name of the b that is related to a
Actually, the two objects I'm dealing with in particular do not
have the same attributes - I want to find the address of a person
who owns an item, but an item can be owned and posessed by
different people, thusly, I'm trying to do something like
item.owner.address - but item also is related to a person by the
item.possessor attribute...
then you want item.possessor.address
Where are you trying to do this? e.g., WebObjects Builder makes it
easy to navigate the key-paths and connect the attribute in question
to the display...
with regards,
--
Lachlan Deck
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