I may play with that suggestion, however the solution that David sent me is 
perfect (and uses Wonder)...
I could not figure out how to traverse the relationships until David showed the 
.dot() format...

Check it out in the mail list.

Ted


--- On Tue, 5/4/10, Joe Kramer <[email protected]> wrote:

From: Joe Kramer <[email protected]>
Subject: Re: qualifierWithQualifierFormat ???
To: "Theodore Petrosky" <[email protected]>
Cc: [email protected]
Date: Tuesday, May 4, 2010, 12:46 PM

Hi Ted,
Couldn't you do something like this where everything in args is an Object?
NSMutableArray args = new NSMutableArray(new Object[] {currentClient, 
"Released"});



openVersionsQualifier = 
EOQualifier.qualifierWithQualifierFormat("versions.versionStatus.versionStatusTitle
 = %@ and client = %@)", args);

readyToBillJobList = Job.fetchDistinctJobs(jobListEC, openVersionsQualifier, 
null);


Hope that helps,
Joe
Joe KramerCyberApps, Inc.


On Tue, May 4, 2010 at 8:55 AM, Theodore Petrosky <[email protected]> wrote:



NSMutableArray<Client>  args = new NSMutableArray<Client>();

args.addObject(currentClient);



openVersionsQualifier = 
EOQualifier.qualifierWithQualifierFormat("versions.versionStatus.versionStatusTitle
 = 'Released' and client = %@)", args);



readyToBillJobList = Job.fetchDistinctJobs(jobListEC, openVersionsQualifier, 
null);



I wanted to put two objects into the args array.

object 1:  String

object 2:  currentClient



but of course args is of type Client so I can not do that... I did try to use 
the primaryKey of currentClient, but then the qualifier is expecting an 
integer... so I casted the string to an int and it worked. but then args is of 
type Integer... still no joy.






so I tried to let the primaryKey be a string but then the qualifier barked it 
needed an integer.



Either I just don't get it or there is an easier way that I just don't see.. If 
I could cast to integer in the qualifier like   " clientid = %@::int", args   
would fix my problem. then I could save all strings in 'args'.






Ted











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