You can construct the EOAndQualifier (or ERXAndQualifier) in code with an
array (or var-args maybe too?).

John

On Tue, May 11, 2010 at 12:34 PM, Theodore Petrosky <[email protected]>wrote:

> Yes it is correct... because I typed it.. I am trying to concat. the
> EOQualifier in my program.
>
> if this.theDescString is null don't add it to the qualifier....
>
> Ted
>
> --- On Tue, 5/11/10, Chuck Hill <[email protected]> wrote:
>
> > From: Chuck Hill <[email protected]>
> > Subject: Re: EOQualifiers (concatenation)
> > To: "Theodore Petrosky" <[email protected]>
> > Cc: [email protected]
> > Date: Tuesday, May 11, 2010, 1:28 PM
> >
> > On May 11, 2010, at 9:48 AM, Theodore Petrosky wrote:
> >
> > > EOQualifier theSearchQualifier0 =
> > ERXQ.is("hasChildren", hasChild);
> > > EOQualifier theSearchQualifier1 =
> > ERXQ.is("isComplete", includeClosedJobs);
> > > EOQualifier theSearchQualifier2 =
> > ERXQ.contains("jobDescription", this.theDescString);
> > >
> > > I have these three qualifiers... If I use them
> > separately, they work exactly as expected.
> > >
> > > How can I add them together to form 1 qualifier to
> > give to the fetch?
> > >
> > > what I want to end up with is:
> > >
> > > EOQualifier theSearchQualifier =
> > ERXQ.and(ERXQ.contains("jobDescription",
> > this.theDescString), ERXQ.is("isComplete",
> > includeClosedJobs), ERXQ.is("hasChildren", hasChild));
> > >
> >
> > Have you tried that?  It looks correct....
> >
> >
> > --Chuck Hill
> >    Senior Consultant / VP Development
> >
>
>
>
>
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