Hi Chuck,
If I want to use WoSwitchComponent in my plist. I code it like that ?
in .plist file :
..
{
title = "HETIC";
keyPath = "col1"; //Here is data
},
{
title = "% de financement"; // Here is component referenced
component = WoSwitchComponentName
}
In my java Method
public WOActionResults addDataToGrid() {
WoSwitchComponentName componentSw = new WoSwitchComponentName(ctxt);//
NSMutableArray dataDico = null;
...
posteDico0.takeValueForKey(data1, "col1");
componentSw.WOComponentName = "myOwnComponentName";
posteDico = new NSMutableArray(posteDico0); ...
This code in my java addData method can work?
Thanks
========================================
Message du : 14/06/2011
De : "Chuck Hill " <[email protected]>
A : [email protected]
Copie à : [email protected]
Sujet : Re: Add a WOComponent in AjaxGrid via a method
Hi Raymond,
AjaxGrid does not support doing it like that. You will need to make your own
WOComponent to put in the cell. There is no other option. Inside that
component, you can use a WOSwitchComponent and determine the actual component
name at runtime based on the row.
WOSwitchComponent
Chuck
On Jun 14, 2011, at 5:43 AM, [email protected] wrote:
Hi All,
I would like to add a WOComponent to a ajaxGrid without necessarily going
through a . plist file, but adds the component that goes well with the data it
will reference via a method. The problem is that is WOComponent not show but
instead it displays the class and subclass of the component. And when I put a
reference component in my. plist file and the "name" of component will be given
when adding to the data, WO gives me an exception because AjaxGrid does not
find the component. In Indeed, this name does not match anything, I take it
like a variable.
i.e : in WOD
addData : WOSubmitButton {
action = addDataToGrid;
value = "Add";
updateContainerID = "dataAjaxGridContainer"; //Update the ajaxGrid
}
in .plist file :
..
{
title = "HETIC";
keyPath = "col1"; //Here is data
},
{
title = "% de financement"; // Here is component referenced
keyPath = "col2"; //keyPath I choosed to add a component
*component = variable // get an exception because the Grid want a component
real name not an variable
}
..
in Java :
public WOActionResults addDataToGrid() {
AjaxGridPopFormInput formInput = new AjaxGridPopFormInput(ctxt);//a WOInput
component
NSMutableArray dataDico = null;
...
posteDico0.takeValueForKey(data1, "col1");
posteDico0.takeValueForKey(formInput, "col2"); //This is my component
posteDico = new NSMutableArray(posteDico0);
...
Resulat :
dataLabel dataComponent
Hello
<projet.rec.utt.server.components.AjaxGridPopFormInput name:
projet.rec.utt.server.components.AjaxGridPopFormInput subcomponents: null >
My Problem is How to display the component correctly?
Thanks for all
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