with_progress() or gen_status()
though for large numbers it'd be nice if it took a kwarg and then only
wrote to stderr if n % kwarg == 0.


On Tue, Jan 6, 2009 at 7:23 AM, Aaron Swartz <[email protected]> wrote:
>
> I'm taking suggestions:
>
> import sys
> def yournamehere(x):
>    lenx = len(x)
>    for n, y in enumerate(x):
>        sys.stderr.write('\r%s/%s = %s' % (n, lenx, float(n)/lenx))
>        yield y
>
> >
>

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