i'm not sure why, but it needed to have the 'to' wrapped with both addresses
in order for the website address to get a copy of the email, but now the
sender and website, both, get a copy of the email - thanks for the help
web.sendmail('[email protected]',[i.email,'[email protected]'],'Message
>From HolyArmor.org', msg,
headers={'Reply-to':i.email,}
)
On Tue, Jul 27, 2010 at 11:46 PM, Zhang Huangbin
<[email protected]>wrote:
>
> On Jul 28, 2010, at 11:32 AM, Greg Milby wrote:
>
> > I did not try headers but tried cc bcc. U suggest I try using with
> sendmail syntax?
>
> I mean just try:
>
> web.sendmail(
> ...SKIP OTHER STUFFS...
> headers=({'Reply-to': '[email protected]',}
> )
>
> Is it what you need?
>
> --
> You received this message because you are subscribed to the Google Groups
> "web.py" group.
> To post to this group, send email to [email protected].
> To unsubscribe from this group, send email to
> [email protected] <webpy%[email protected]>.
> For more options, visit this group at
> http://groups.google.com/group/webpy?hl=en.
>
>
--
You received this message because you are subscribed to the Google Groups
"web.py" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/webpy?hl=en.
