On Sep 23, 6:19 pm, Greg Milby <[email protected]> wrote:
> are you trying to call the same file twice?
Nope, don't even know how I could do this...
The environment in which I use web.py is a daemon with multiple
processes manages via the "multiprocessing" module. Many different
kinds of workers work on different queues. One of the workers is a
HTTP-REST interface to submit jobs to the initial queue. That's what
I use web.py for... So from the command line, I launch the daemon
process that spans and supervises all workers, including web.py...
I looked through the source and found a solution:
import web
class MyApplication(web.application):
def run(self, port=8080, *middleware):
func = self.wsgifunc(*middleware)
return web.httpserver.runsimple(func, ('0.0.0.0', port))
#--------------------------
urls = ('/', 'hello')
class hello:
def GET(self):
return 'Hello'
if __name__ == "__main__":
app = MyApplication(urls, globals())
app.run(port=8888)
Since I don't need cgi etc., that works for me. Redefining "run" in a
subclass seemed to be the easiest way..
In case you like the optional "port" argument in application.run, I
could possibly prepare a patch.. Let me know.
best cheers
-b
--
You received this message because you are subscribed to the Google Groups
"web.py" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/webpy?hl=en.
