In the Site Layout example, it shows that you should be able to do
this in templates:
> $if content.cssfiles:
> $for f in content.cssfiles.split():
> <link rel="stylesheet" href="$f" type="text/css"
media="screen" charset="utf-8"/>
But whenever I try this, I get an error if content.cssfiles does not
exist.
So far I have solved this by putting a blank "$var cssfiles:" in all
my templates, but this seems like a hack-y workaround.
Anyone know what I could be missing?
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