In your regular expression, there is a grouping -- anything wrapped in
parentheses becomes a group. webpy calls your get method with that
passed as an argument, so you need to update your GET prototype to
look like:
def GET(self, arg1):
Then you can use that argument in your code. This is handy for
something like:
urls =
'/get_widget/(.+)', 'GetWidget'
)
and then you can do something like:
class GetWidget:
def GET(self, widget_id):
widget = db.select('widgets', where="id=$widget_id", vars=locals())
[0]
return render.get_widget(widget)
Hope this helps.
-Justin
On Jan 26, 2:36 pm, Giovanni <[email protected]> wrote:
> I'm trying to match DOIs in the requests and I have some problems.
>
> My code is the following.
>
> I have a simple (generic and not complete) regular expression for the
> DOIs:
> urls = (
> '/(doi\:)?10\.[0-9]{4}\/.*','doi',
> )
>
> class doi(object):
> """Class that takes care of a DOI"""
> def __init__(self):
> """ Constructor"""
> pass
> def GET(self):
> """manager of the get requests"""
> print 'doi'
>
> but this code gives me an error if I call my server with the
> URLhttp://localhost:8000/10.1088/0004-637X/726/2
>
> the error is the following:
>
> - - [26/Jan/2011 17:00:19] "HTTP/1.1 GET /101088" - 500 Internal
> Server Error
> Traceback (most recent call last):
> File "/opt/local/Library/Frameworks/Python.framework/Versions/2.5/
> lib/python2.5/site-packages/web/application.py", line 242, in process
> return self.handle()
> File "/opt/local/Library/Frameworks/Python.framework/Versions/2.5/
> lib/python2.5/site-packages/web/application.py", line 233, in handle
> return self._delegate(fn, self.fvars, args)
> File "/opt/local/Library/Frameworks/Python.framework/Versions/2.5/
> lib/python2.5/site-packages/web/application.py", line 415, in
> _delegate
> return handle_class(cls)
> File "/opt/local/Library/Frameworks/Python.framework/Versions/2.5/
> lib/python2.5/site-packages/web/application.py", line 390, in
> handle_class
> return tocall(*args)
> TypeError: GET() takes exactly 1 argument (2 given)
>
> I'm running python code on Mac OS X 10.5.8 with python 2.5 (port
> version).
>
> What's wrong with my code?
> I think the problem is in the regular expression, but I cannot figure
> out what it is.
>
> Thanks in advance!
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