Am 11.02.2012 08:50, schrieb Primoz Anzur:
Maybe you've wanted Image.frombuffer() or Image.fromstring()?
I tried, but to "convert" a File Object to an Image - File Object i read
to use Image.open(file).
I dont want to use tmp_file or write it to disk, because i use GridFS to
store Files.
On Sat, Feb 11, 2012 at 8:47 AM, Primoz Anzur <[email protected]
<mailto:[email protected]>> wrote:
This is not how you use PIL
http://www.pythonware.com/library/pil/handbook/image.htm
Image.open(infile) => image
Image.open(infile, mode) => image
On Fri, Feb 10, 2012 at 7:58 PM, Patrick Erdmann
<[email protected] <mailto:[email protected]>> wrote:
f is image data, see here:
x = web.input(bilder={})
b.set_image(x.bilder.file)
----
f = x.bilder.file
----
Am 09.02.2012 16:23, schrieb Primoz Anzur:
What is 'f'? Is it image data or the filename?
On Thu, Feb 9, 2012 at 12:38 PM, Patrick Erdmann
<[email protected] <mailto:[email protected]>
<mailto:[email protected] <mailto:[email protected]>>>
wrote:
Hi,
when i try to upload images i get following Error:
UnicodeDecodeError: 'utf8' codec can't decode byte 0xff
in position
0: invalid start byte
. Everything works fine until i call Image.open(f), from
PIL import
Image.
x = web.input(bilder={})
b = Bilder()
b.set_image(x.bilder.file)
b.save()
...
class Bilder(Document):
...
def set_image(self, f):
_i = Image.open(f, 'wb')
...
--
Mit freundlichen Grüßen
Patrick Erdmann
XMPP/Mail: [email protected]
<mailto:[email protected]> <mailto:[email protected]
<mailto:[email protected]>>
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