You have to do: rs.sort(lambda a, b, i=i: cmp(a[i], b[i]))
On Wed, 2001-11-28 at 13:17, Aaron Held wrote: > Is there an easy way to sort a nested list by passing a param to the sort routine? > > I can sort on any index via > rs.sort(lambda a,b:cmp(a[0],b[0])) > > but I cannot figure out how to make the list index a variable > rs.sort(lambda a,b:cmp(a[ i ],b[ i ])) > > Any ideas? > > -Aaron > > > > _______________________________________________ > Webware-discuss mailing list > [EMAIL PROTECTED] > https://lists.sourceforge.net/lists/listinfo/webware-discuss > _______________________________________________ Webware-discuss mailing list [EMAIL PROTECTED] https://lists.sourceforge.net/lists/listinfo/webware-discuss
