On Wed, 2003-01-15 at 13:43, Randy Heiland wrote: > First, thanks to those who responded, primarily with pointers to > http://xml.apache.org/xmlrpc/ . I installed that pkg and saw the sample > client, however, I still need some handholding. > > First, let me be clear, I want to connect to the WebKit/AppServer Python server > from a Java client. Can someone tell me what the params to XmlRpcClient would > be? E.g., should hostName = > "http://myhost/cgi-bin/WebKit.cgi/Examples/XMLRPCExample"; > > What about SERVER_PORT? > > client = new XmlRpcClient(hostName, SERVER_PORT);
Don't worry about that -- that's just like http://myhost:8080/, where 8080 is the port -- apparently you can specify the port separate from the URL. >From what I can see, you just want to use: XmlRpcClient("http://myhost/cgi-bin/WebKit.cgi/Examples/XMLRPCExample";) -- Ian Bicking Colorstudy Web Development [EMAIL PROTECTED] http://www.colorstudy.com PGP: gpg --keyserver pgp.mit.edu --recv-keys 0x9B9E28B7 4869 N Talman Ave, Chicago, IL 60625 / (773) 275-7241 ------------------------------------------------------- This SF.NET email is sponsored by: A Thawte Code Signing Certificate is essential in establishing user confidence by providing assurance of authenticity and code integrity. Download our Free Code Signing guide: http://ads.sourceforge.net/cgi-bin/redirect.pl?thaw0028en _______________________________________________ Webware-discuss mailing list [EMAIL PROTECTED] https://lists.sourceforge.net/lists/listinfo/webware-discuss
