Am Donnerstag, 18. Januar 2018 15:00:21 UTC+1 schrieb Tom Keffer:

>
> I'm not sure what you mean by replacing 2017 by a variable. 
>

I will make a spreadsheet like :

*year  high-wind days*





*2015   252016   312017   28 *

and I want to replace the year-value with a variable like $date(yyyy) -1, 
$date(yyyy) -2, etc . ,
but which variable works?

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