hi,
i want wget to post a form which contains 3 fields and a file to upload
(enctype="multipart/form-data")
http://www.pchelpware.com/creator/index.html
i found out, using the option
--post-file "C:\form.bin"
that C:\form.bin has to look something like:
-----------------------------202481336020143
Content-Disposition: form-data; name="upload_file"; filename="test.zip"
Content-Type: application/zip
[here comes the binary of the zip-file]
-----------------------------202481336020143
Content-Disposition: form-data; name="userid"
foo
-----------------------------202481336020143
Content-Disposition: form-data; name="password"
foobar
-----------------------------202481336020143
Content-Disposition: form-data; name=".submit"
Upload
-----------------------------202481336020143--
so far, so good.
but it only works half because wget is sending this with the header:
CONTENT_TYPE: application/x-www-form-urlencoded
while the server of course only accepts:
CONTENT_TYPE: multipart/form-data; boundary=-...-202481336020143
if i use the --header option, this header becomes:
HTTP_CONTENT_TYPE: multipart/form-data; boundary=----...
and wget still uses
CONTENT_TYPE: application/x-www-form-urlencoded
how can i force wget to send the correct CONTENT_TYPE?
or what else am i doing wrong?
regards, gerhard
