Am 17.09.2010, 20:46 Uhr, schrieb Anne van Kesteren <[email protected]>:
On Fri, 17 Sep 2010 20:41:19 +0200, Dennis Joachimsthaler
<[email protected]> wrote:
(Or, any knowledge how it is done today? I can't find
anything about it! Crazy.)
Of course:
http://dev.w3.org/2006/webapi/XMLHttpRequest-2/#the-formdata-interface
Oh? It doesn't seem to allow me to insert files though. And where do I set
the content-type?
Currently I am trying it like this:
xhr.open("POST", "/Post/Add");
xhr.setRequestHeader("Content-Type", "multipart/form-data;
boundary=HELLOWORLD");
xhr.send("--HELLOWORLD\r\n");
xhr.send("Content-Disposition: form-data; name=\"tags\"\r\n");
xhr.send("\r\n");
xhr.send("tags");
xhr.send("\r\n");
xhr.send("--HELLOWORLD\r\n");
xhr.send("Content-Disposition: form-data; name=\"title\"\r\n");
xhr.send("\r\n");
xhr.send("tags");
xhr.send("\r\n");
xhr.send("--HELLOWORLD\r\n");
xhr.send("Content-Disposition: form-data; name=\"file\"\r\n;
filename=\"Hallo.jpg\"\r\n");
xhr.send("Content-Type: " + "image/jpeg\r\n");
xhr.send("\r\n");
xhr.sendAsBinary(file.getAsBinary());
xhr.send("\r\n");
xhr.send("--HELLOWORLD--\r\n");
Downside is that the first send() will end the request already.
The file variable is a file gotten from the FileApi.
