but it's not. URI's have a very specific syntax. this method returns a Class, which is not a URI (which is a java.net class). this would confuse the casual observer. it would confuse me as well!
Gili wrote:
But in Wicket's case, the class *is* used as a URI. The only reason you are getting the Page class is so you can find out whether the link points to the current page or not. Getting the URI would do that and it is more intuitive.
Gili
On Tue, 25 Jan 2005 15:59:11 -0800, Jonathan Locke wrote:
but that's not what it does. i think better docs are the solution. it gets the class of Page not the URI.
can you submit a bug that this needs to be documented? i don't want us to foget it.
thanks,
jon
Gili wrote:
My 2 cents: the name getPageClass() is the source of this confusion. Everyone naturally assumes that getPageClass() is redundant because you could use getPage().getClass() but if you renamed it to getPageURI() or something it would make a lot more sense to people. Also, getPageClass()'s online Javadoc is empty which is also contributing to the problem.
Gili
On Tue, 25 Jan 2005 09:10:10 -0800, Jonathan Locke wrote:
Juergen Donnerstag wrote:
nope. getPage() actually resolves the Page when a link is clicked. getPageClass is part of the information used before the link is clicked to determine how a link should be rendered.IPageLink requires us to implement two methods: getPage() and getPageClass(). Aren't these two information redundant? The page
the docs state this:
* ... The getPageClass()
* method returns the subclass of Page that getPage() will return if
* and when it is called. * <p>
* This way of arranging things is useful in determining whether a
* link links to a given page, which is in turn useful for deciding
* how to display the link (because links in a navigation which link to
* a page itself are not useful and generally should instead indicate
* where the user is in the navigation).
returned by getPage() is able to provide its Class. From the sources I understand what they required for, but from a user's perspective I don't. Does anybody knwo the details of this implementation and may be come up with a suggestion on how to avoid getPageClass() in IPageLink.
Juergen
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