I would like to use ajax behaviour because if there are validation error I can notify user for errors without reloading page again.
If validation is OK I need to move to the next page in the application flow so in the onSubmit method for AjaxFormSubmitBehavior I write
protected void onSubmit(AjaxRequestTarget target) {
if( getFeedbackMessages().isEmpty() ) {
MyPage page = new MyPage(...);
String url = "" RequestCycle.get().urlFor(page, IRedirectListener.INTERFACE );
target.addJavascript ( "window.location = '" +url+ "'" );
} else {
target.addJavascript("alert('"+ getJavascriptFeedbackMessage() +"')");
}
}
Thanks, Paolo
On 7/25/06, Johan Compagner <[EMAIL PROTECTED]> wrote:
need to see some more code or a test case.On 7/25/06, Paolo Di Tommaso < [EMAIL PROTECTED]> wrote:I'm trying to redirect after an ajax request doing something like that:
String url = "" RequestCycle.get().urlFor(myPageInstance, IRedirectListener.INTERFACE );
target.addJavascript( "window.location = '" +url+ "'" );
But always get an "Page Expired" error page.
Is it possible to redirect to a page instance?
Thanks, Paolo
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