Thanks Igor.
We're not ready for Ajax yet.
What if I don't mind having to reload the original page (that contains the
form) and then show the popup straight-away?
ie once the page is submitted, reload the page and show the modal popup as
soon as the page is loaded? (of course, the popup is not wanted when the
page is navigated to from elsewhere, only when the form is submitted).
igor.vaynberg wrote:
>
> what you would have to do is submit the form via ajax, then in onsubmit
> add
> some javascript to the ajax request target that shows the popup.
>
> -igor
>
> On 5/11/07, howzat <[EMAIL PROTECTED]> wrote:
>>
>>
>> Wicket 1.2.6:
>> When the user clicks the submit button on a form, I would like to first
>> perform some logic on the server side (eg persist some stuff the user
>> has
>> entered), and if this server side logic completes successfully I would
>> like
>> to display a "success confirmed, hit ok to continue" modal popup. When
>> the
>> user closes this modal pop-up I would like to return to the application's
>> home-page.
>> I am trying to do this by overriding the form's onSubmit method;
>> public void onSubmit() {
>> boolean success = doSomeServerSideStuff(dataInputByUserIntoTheForm);
>> if (success){
>> // (a) show a "success confirmed, hit ok to continue" modal
>> popup;
>> // (b) go to home page
>> } else {
>> // ...
>> }
>> }
>>
>> The code I find in the wicket examples and google use PopupSettings and
>> Popup (the latter seems no longer to exist).
>>
>> 1 - Does anybody have a 1.2.6 snippet to demonstrate this how to achieve
>> (a)
>> and (b)?
>> 2 - To get back to the home-page, I am using setResponsePage(new
>> MyAppsHomePage()). Is that the right way to go back to the
>> home-page? Does
>> that mean I need to create a new instance of the home-page each time I
>> want
>> to go back there or is there a cached instance that I can use (assuming
>> that
>> the user has arrived at the current page via the home page)?
>> --
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>> Sent from the Wicket - User mailing list archive at Nabble.com.
>>
>>
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