Sure :)
In page 1 you do add(new PageLink("start", Foo.class));
because you are using the class reference to your 2nd page here wicket
always creates a new instance, the same happens with the pagelink on
page2 where you go back to page 1.
The trick is to tell wicket to use an existing page.
so on page 1 we could do this
add(new PageLink("start", new IPageLink()
{
public Page getPage()
{
//now we can decide which instance / constructor we use
//in this case a new page is fine
return new Foo(HelloWorld.this);
}
public Class getPageIdentity()
{
return Foo.class;
}
}));
Because we now pass the first page to the 2nd page we need to alter
the constructor of the 2nd page
public Foo(Page returnPage) {
add(new Label("message", "Foo page"));
//this basically wraps your page in an IPageLink like we did manually on page 1
Link pl = new PageLink("return", returnPage);
pl.add(new AttributeAppender("class", new Model("return"), " "));
add(pl);
}
And thats all there is to it.
And i did not even have to use a regular link like i though we would
have to in my previous response :)
Maurice
On 6/26/07, Leucht, Axel <[EMAIL PROTECTED]> wrote:
> Thx for the quick answer, but being a newbie can I ask you to elaborate it a
> little bit more?
>
> Regards
>
> /Axel
>
>
> >>-----Ursprüngliche Nachricht-----
> >>Von: [EMAIL PROTECTED]
> >>[mailto:[EMAIL PROTECTED] Auftrag
> >>von Maurice
> >>Marrink
> >>Gesendet: Dienstag, 26. Juni 2007 11:07
> >>An: wicket-user@lists.sourceforge.net
> >>Betreff: Re: [Wicket-user] newbie-Question
> >>
> >>
> >>You need to pass a reference for page 1 to page 2 and then instead of
> >>using a pagelink on page2 to return to page1 use a regular link which
> >>sets the responsepage to the instance of page 1 you passed to page 2.
> >>
> >>Maurice
> >>
> >>On 6/26/07, Leucht, Axel <[EMAIL PROTECTED]> wrote:
> >>> Sorry if this is a dumb question and has been answered
> >>hundred times but I couldn't find any answer to the following
> >>question.
> >>>
> >>> I do have two HTML pages. Page one contains a link which
> >>displays the number on clicks the user executed. The second
> >>link jumps to page 2. Page 2 just displays a link to go back
> >>to page 1.
> >>>
> >>> Assume that user clicks 5 times on the ClickCounter link in
> >>page 1 and hence the link displays as 'This link is clicked 5
> >>times'. When the user the switches to page 2 and immediately
> >>goes back to page 1 the counter is reset to 0 and rendered as
> >>'This link is clicked 0 times'.
> >>>
> >>> What am I doing wrong here? I assumed that clicking on the
> >>return-button on page 2 goes "back" to the original session
> >>in page 1 ?!
> >>>
> >>> Here is my Java classes:
> >>> -- page 1 ---
> >>> public class HelloWorld extends WebPage implements Serializable {
> >>> public HelloWorld() {
> >>> add(new Label("message", "Foo World!"));
> >>> add(new PageLink("start", Foo.class));
> >>> final ClickCount count1 = new ClickCount();
> >>> Link link1 = new Link("link1") {
> >>> public void onClick() {
> >>> count1.clicks++;
> >>> }
> >>> };
> >>> link1.add(new Label("label1", new Model() {
> >>> public java.lang.Object
> >>getObject(Component component) {
> >>> return
> >>Integer.toString(count1.clicks);
> >>> }
> >>> }));
> >>> add(link1);
> >>> }
> >>>
> >>> class ClickCount implements Serializable {
> >>> private int clicks = 0;
> >>> }
> >>> }
> >>> --- page 2 ---
> >>> public class Foo extends WebPage {
> >>> public Foo() {
> >>> add(new Label("message", "Foo page"));
> >>> Link pl = new PageLink("return", HelloWorld.class);
> >>> pl.add(new AttributeAppender("class", new
> >>Model("return"), " "));
> >>> add(pl);
> >>> }
> >>> }
> >>> /Axel
> >>>
> >>>
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