why do you expect that the Seebeck is symmetric arround zero chemical potential 
(whatever you assume to be the Zero)
is your density of states symmetric with respect to the middle of the band gap ?

Ciao
Gerhard

DEEP THOUGHT in D. Adams; Hitchhikers Guide to the Galaxy:
"I think the problem, to be quite honest with you,
is that you have never actually known what the question is."

====================================
Dr. Gerhard H. Fecher
Institut of Inorganic and Analytical Chemistry
Johannes Gutenberg - University
55099 Mainz
and
Max Planck Institute for Chemical Physics of Solids
01187 Dresden
________________________________________
Von: wien-boun...@zeus.theochem.tuwien.ac.at 
[wien-boun...@zeus.theochem.tuwien.ac.at] im Auftrag von hannan.sa...@uv.es 
[hannan.sa...@uv.es]
Gesendet: Montag, 4. April 2016 06:34
An: A Mailing list for WIEN2k users
Betreff: [Wien] Seebeck coefficient_Boltztrap

Dear Wien2k users;
I'm using the boltztrap code to study the thermoelectric properties of some 
semiconducting materials.
I run the process and I got the results. But I have a problem; when I drew the 
figure that represents the Seebeck coefficient as a function of the chemical 
potential, I didn't get the curve symmetric around zero chemical potential. I 
got the curve at the right of the zero chemical potential.
Also I tried to reproduce the examples that are given in the package like 
Bi2te3, to know if it is happened only with these materials, and I had the same 
problem.
What could be the mistake that I did in the calculations?
Best regards
Hannan

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