Please find enclosed brj.f file.
Sincerely
------------------------------------------------
Dr. K. C. Bhamu
(UGC-Dr. D. S. Kothari Postdoc Fellow)
Department of Physics
Goa University, Goa-403 206
India
Mob. No. +91-9975238952
On Tue, Oct 25, 2016 at 5:04 PM, <[email protected]> wrote:
> In this case I don't understand why lapw0 is hanging. Can you
> send the subroutine brj.f?
>
> On Tuesday 2016-10-25 12:18, Dr. K. C. Bhamu wrote:
>
> Date: Tue, 25 Oct 2016 12:18:41
>> From: Dr. K. C. Bhamu <[email protected]>
>> Reply-To: A Mailing list for WIEN2k users <[email protected].
>> at>
>> To: A Mailing list for WIEN2k users <[email protected]>
>> Subject: Re: [Wien] regarding hanging of job and mBJ
>>
>>
>> Probably your are using an old version of WIEN2k with the old
>> scheme
>> to find the solution of the nonlinear equation in brj.f. You
>> should get
>> the new version brj.f which avoids such problems.
>>
>>
>> No, I am using latest version of Wien2k with mkl+ifort.
>> It is not for all case. It happens for few cases and it doesn't matter
>> that
>> which case I am running.
>>
>> _______________________________________________
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>> SEARCH the MAILING-LIST at:
>> http://www.mail-archive.com/[email protected]
>> /index.html
>>
>>
>>
>>
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>
subroutine brj(rho,grho,g2rho,tau,vxbrj,ir)
!A. D. Becke and M. R. Roussel, Phys. Rev. A 39, 3761 (1989).
!A. D. Becke and E. R. Johnson, J. Chem. Phys. 124, 221101 (2006).
!E. Proynov, Z. Gan, and J. Kong, Chem. Phys. Lett. 455, 103 (2008).
use xcparam
implicit real*8(a-h,o-z)
real*8 :: a(1:3), b(0:5), c(0:5), d(0:5), e(0:5), yp(0:5)
save iint,isphere
data iint/0/,isphere/0/
pi = 4d0*atan(1d0)
vxbrj = 0d0
if (rho .gt. 1d-18) then
tautf = (3d0/10d0)*(3d0*pi**2)**(2d0/3d0)*(2d0*rho)**(5d0/3d0)
tauw = 0.125d0*grho*grho*2.d0/rho
if (tau.lt.tauw) then
tau_falsch=tau
tau=tauw
endif
if (tau.eq.tauw .and. rho.lt.10.d0.and.ir.lt.900.and.isphere.eq.0) then
print*,'sphere:rho,tauw,grho,g2rho',rho,tau,grho,g2rho,'tauwrong=',tau_falsch
isphere=1
endif
if (tau.eq.tauw .and. ir.gt.900.and.iint.lt.10) then
print*,'int:rho,tauw,grho,g2rho',rho,tau,grho,g2rho,'tauwrong=',tau_falsch
iint=iint+1
endif
a(1) = 1.5255251812009530d0
a(2) = 0.4576575543602858d0
a(3) = 0.4292036732051034d0
c(0) = 0.7566445420735584d0
c(1) = -2.6363977871370960d0
c(2) = 5.4745159964232880d0
c(3) = -12.657308127108290d0
c(4) = 4.1250584725121360d0
c(5) = -30.425133957163840d0
b(0) = 0.4771976183772063d0
b(1) = -1.7799813494556270d0
b(2) = 3.8433841862302150d0
b(3) = -9.5912050880518490d0
b(4) = 2.1730180285916720d0
b(5) = -30.425133851603660d0
d(0) = 0.00004435009886795587d0
d(1) = 0.58128653604457910d0
d(2) = 66.742764515940610d0
d(3) = 434.26780897229770d0
d(4) = 824.7765766052239000d0
d(5) = 1657.9652731582120d0
e(0) = 0.00003347285060926091d0
e(1) = 0.47917931023971350d0
e(2) = 62.392268338574240d0
e(3) = 463.14816427938120d0
e(4) = 785.2360350104029000d0
e(5) = 1657.962968223273000000d0
dd = tau - 0.25d0*grho**2/rho
q = (g2rho - 1.6d0*dd)/6d0
if (abs(q) .gt. 1d-18) then
y = (2d0/3d0)*pi**(2d0/3d0)*rho**(5d0/3d0)/q
do i=0, 5
yp(i) = y**i
enddo
if (y .le. 0d0) then
g = -atan(a(1)*y + a(2)) + a(3)
p1 = sum(c(0:5)*yp(0:5))
p2 = sum(b(0:5)*yp(0:5))
elseif (y .gt. 0d0) then
z = 2.085749716493756d0*y
g = log(sqrt(1d0 + 1d0/z**2) + 1d0/z) + 2d0
p1 = sum(d(0:5)*yp(0:5))
p2 = sum(e(0:5)*yp(0:5))
endif
if (abs(p2) .gt. 1d-18) then
x = g*p1/p2
if (abs(x) .gt. 1d-18) then
vxbrj = -2d0*pi**(1d0/3d0)*rho**(1d0/3d0)*exp(x/3d0)/x*(1d0 - exp(-x) - 0.5d0*x*exp(-x))
if (tau .ge. 0d0) then
vxbrj = xcconst*vxbrj + (3d0*xcconst-2d0)*sqrt(5d0/12d0)/pi*sqrt(tau/rho)
else
vxbrj = xcconst*vxbrj - (3d0*xcconst-2d0)*sqrt(5d0/12d0)/pi*sqrt(abs(tau/rho))
endif
endif
endif
endif
endif
return
end
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