Thank you Prof. Gavin Sir
I  did not see any factorization error. or similar that I could fix with your 
inputs and my understanding.I also tried to run various calculations with Ipfac 
from 5 to 100 but the error still persists. What I see changes are the error 
occurred at different temperature values in different Ipfac value.It is an 
alloyed structure. For parent structure, I did not see any error up to 1E22 
(1E18 to 1E22) doping level while in alloyed structure I faced Fermi error at 
4E21 doping level.
The error message might be due to the alloying element. I do not have much 
knowledge about how much carrier concentration may be possible in a structure. 
So If we replace a lower Z element by a high Z element from the same group 
(7A), then there may be some limitation of doping levels. But I do not know 
about this domain. 
The exact error message is:
 ================ BoltzTraP vs 1.2.5 ============= 6E21                         
                                                    XXXXXXXX  0.351378446329918 
     -0.234775561786487       5.000000000000000E-004 npoints        1173Doping 
level number     1 n =  0.600E+22 carriers/cm3  Doping corresponds to    
1.64561901912858       excess holes per unit cellDoping level number     2 n = 
-0.600E+22 carriers/cm3  Doping corresponds to   -1.64561901912858       excess 
electrons per unit cell Error - Fermi level was not found for doping            
2  at temperature    400.000000000000      Error - Fermi level was not found 
for doping            2  at temperature    500.000000000000     72.2u 0.1s 
1:13.58 98.4% 0+0k 0+33848io 0pf+0w
 

    On Sunday, 30 July 2017 10:41 PM, chin Sabsu <chinsa...@yahoo.in> wrote:
 

 Dear Users,After successful attempt of electronic, optical and magnetic 
properties, I tried to run Boltztrap calculation.In an alloyed compound with 
different doping level concentrations, I encountered below error.
"Error - Fermi level was not found for doping"

Please suggest me:What does it mean and how to overcome this situation.

Thanks in advance and help will be highly appreciated.
Thank youChin

   
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