--- Comment #4 from Bugzilla Bug Importer (valhallasw) 
<> ---
From: Hoo man <>
Date: Thu, 06 Jan 2011 17:51:48

You can't, but I can, with a slightly modified query:

    SELECT user.user_name as user, COUNT(logging.log_user) as reviews FROM
logging INNER JOIN user ON logging.log_user = user.user_id INNER JOIN
user_groups ON user_groups.ug_user = user.user_id WHERE user_groups.ug_group =
"editor" AND logging.log_type = "review" AND logging.log_action != "approve-a"
GROUP BY user ORDER BY reviews DESC;

Result: (new results) (old results)

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