https://bugzilla.wikimedia.org/show_bug.cgi?id=29542
--- Comment #1 from Brion Vibber <[email protected]> 2011-06-23 18:17:16 UTC --- Might work to do something like using a placeholder <span/> and then .replace() the links into it: var $foo = $( "<div>This is a <b><span id='qqq1'></span></b> link</div>" ) $.each(paramList, function(i, link) { $foo.find('#qqq' + i).replace(link); }); -- Configure bugmail: https://bugzilla.wikimedia.org/userprefs.cgi?tab=email ------- You are receiving this mail because: ------- You are on the CC list for the bug. _______________________________________________ Wikibugs-l mailing list [email protected] https://lists.wikimedia.org/mailman/listinfo/wikibugs-l
