Chicocvenancio added a comment.

  In T230135#5403134 <https://phabricator.wikimedia.org/T230135#5403134>, 
@OlafJanssen wrote:
  
  > @Chicocvenancio Thanks for elegant your solution. I looked at 
https://stackoverflow.com/questions/10606133/sending-user-agent-using-requests-library-in-python
 
  > I added this the notebook, is that a valid approach as well? (I'm not 
experienced with this sort of stuff yet)
  >
  >  --------------------------------------------
  >
  > import requests
  >  url = 'http://www.kb.nl'
  >  headers = {
  >
  >   'User-Agent': 'My User Agent 1.0',
  >   'From': '[email protected]'  # This is another valid field
  >
  > }
  >  response = requests.get(url, headers=headers)
  
  That won't change the UserAgent used by SPARQLWrapper. SPARQLWrapper has an 
`agent` parameter you can use that will solve this.
  
    ...
    def get_results(endpoint_url, query):
        sparql = SPARQLWrapper(endpoint_url, agent='OlafJanssen from PAWS')
    ...
  
  Is one way to get this working.

TASK DETAIL
  https://phabricator.wikimedia.org/T230135

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To: Chicocvenancio
Cc: Lucas_Werkmeister_WMDE, Chicocvenancio, OlafJanssen, darthmon_wmde, 94rain, 
DannyS712, Nandana, Lahi, Gq86, R96340, GoranSMilovanovic, Allthingsgo, 
QZanden, EBjune, merbst, LawExplorer, Framawiki, _jensen, rosalieper, Jonas, 
Xmlizer, Jane023, jkroll, Smalyshev, Wikidata-bugs, Jdouglas, Xqt, aude, 
Tobias1984, yuvipanda, Capt_Swing, Manybubbles, zhuyifei1999, Mbch331
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