Hi Thad,
Did it ever works?
It was my understanding that if you want to manipulate the label (or the
description, or the alias), you need to explicitly call it and that the
SERVICE was for display only. At least, this is with this assumption that I
always wrote my query (or explained during SPARQL workshops) :/
Anyway, this query works :
SELECT ?item ?itemLabel WHERE {
?item wdt:P31 wd:Q2085381 ; rdfs:label ?itemLabel .
FILTER(CONTAINS(LCASE(?itemLabel), "simon"))
FILTER (LANG(?itemLabel)="en")
}
Cheers,
~nicolas
Le ven. 31 mai 2019 à 03:05, Thad Guidry <[email protected]> a écrit :
> My Query:
>
> SELECT ?item ?itemLabel WHERE {
> ?item wdt:P31 wd:Q2085381.
>
> SERVICE wikibase:label { bd:serviceParam wikibase:language
> "[AUTO_LANGUAGE],en". }
> # FILTER(CONTAINS(LCASE(?itemLabel), "simon"))
> # FILTER (LANG(?itemLabel)="en")
> }
>
> and if I enable any of the FILTER lines, it returns 0 results.
> What changed / Why ?
>
> Thad
> https://www.linkedin.com/in/thadguidry/
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