On Mon, Jan 5, 2009 at 11:54 PM, Greg L <[email protected]>wrote:
> Hi, > > I'm new to this venue so please have patience with me. Jimbo suggested > I contact Erik and Erik said I should post here. > > Wikipedia authors of magic words and templates could really use a > character-counting parser function. All the background information can > be found here: > > > http://en.wikipedia.org/w/index.php?title=User_talk:Jimbo_Wales&oldid=260819871 > - Developer_support_for_parser_function > > In a nutshell though, there is currently a template on en.Wikipedia > called {{val}} that delimits numbers (places what appears to be > thinspaces very three characters in scientific notation). It currently > must use math-based techniques to parse the value and this results in > rounding errors 5–10% of the time. > > A character-counting parser function would accept interrogations such > as "Are there more than four characters remaining in the string when > counting right from the decimal point?" And "If so, feed me three more > characters." Such a parser function would be very handy for many other > purposes. With a good, bullet-proof parser function, our small army of > template authors could produce some nice new tools. > > I can be reached at [email protected] > > Greg > _______________________________________________ > Wikitech-l mailing list > [email protected] > https://lists.wikimedia.org/mailman/listinfo/wikitech-l > There's http://www.mediawiki.org/wiki/Extension:StringFunctions, but it had some issues (which caused a reversal of a merge with Parser Functions). IIRC, it was mentioned at the time that without some improvements, it wouldn't get enabled on WMF wikis. -Chad _______________________________________________ Wikitech-l mailing list [email protected] https://lists.wikimedia.org/mailman/listinfo/wikitech-l
