User "Bryan" posted a comment on MediaWiki.r85207.
Full URL:
https://secure.wikimedia.org/wikipedia/mediawiki/wiki/Special:Code/MediaWiki/85207#c15916
Comment:
Well, that is an interesting way to calculate a sharpening matrix. But I guess
if it works for them it will work for us as well.
For my own reference:
<math>K_{ij} = -\frac{1}{2\pi\sigma^2} e^{\frac{i^2+j^2}{2\sigma^2}};</math>
<math>K_{00} = -2\sum\sum K_{ij}</math>
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