"Francois Gouget" <[EMAIL PROTECTED]> wrote:
> > +#if !defined(_stdcall)
> > #define _stdcall __stdcall
> > #define _fastcall __stdcall
> > #define __fastcall __stdcall
> > +#endif
>
> Is _stdcall going to be a macro? I would rather expect it to be a
> reserved keyword like in Visual C++.
Certainly I don't know whether _stdcall is a macro or not, but the
construction below compiles correctly without warnings by both cl and gcc.
#if !defined(_stdcall)
#define _stdcall __stdcall
#endif
#define WINAPI _stdcall
typedef unsigned long DWORD;
extern DWORD WINAPI GetLastError(void);
int main(void)
{
return GetLastError() != 0xdeadbeef;
}
--
Dmitry.
