> Hm, so if you declare an array like so: > > DWORD args[32]; > > and then pass args as a parameter of type "DWORD *args", it > automatically gets the address of it? I thought passing variables > directly like that would normally cause a copy by value, but I don't > know C well enough I suppose. >
yes. As far as parameter passing goes, xxx *bob is the same as xxx bob[]. this is always true in C and C++, as far as I can remember. Kelly
