if Point B is the WAP11, then you will get 1/2 the throughput.
i.e. if you were getting 4.4 Mbps from AtoB and 4.4 Mbps from BtoC
then you will get 2.2 Mbps from AtoC.
Why: the WAP11 is not Full-Duplex over the air. It has to recieve a packet
from StationA then send the packet to StationC. Then receive a packet from
StationC then send that packet back to StationA. On and on and on.
Example: Imagine three men in a row. MAN1 --- MAN2 --- MAN3
The man in the middle (MAN2) has one only one hand to hold 1 potatoe. He has
to get 50 potatoes from MAN1 all the way to MAN3. He can never hold two (2)
potatoes at a time. Just (1) potatoe.
Now image that MAN3 has 100 potatoes to get over to MAN1 !!!
MAN1(50) ---- MAN2 ----- MAN3(100)
Get it? The WAP11* can only handle one transaction at a time.
So your bottleneck is the WAP11. A quick solve is to use 2 WAP11s in the
middle connected together with a cross-over eth cable.
This will give nearly full bandwidth of 4 Mbps
* All 802.11b APs are the same way
=====
Dan Kramarsky
RF Engineer
SpeedBand, Inc.
=- Wireless Internet Service Provider -=
phone: 909-551-7358
web: www.speedband.com
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