On Fri, Apr 25, 2008 at 7:49 PM, Luis EG Ontanon <[EMAIL PROTECTED]> wrote:
> On Fri, Apr 25, 2008 at 10:17 PM, Jeff Morriss > <[EMAIL PROTECTED]> wrote: > > Guy Harris wrote: > > > > > http://www.cs.berkeley.edu/~wychen/cs261/proposal.htm<http://www.cs.berkeley.edu/%7Ewychen/cs261/proposal.htm> > > > > If Figure 1 is really a problem then my understanding of C just went out > > the window... > > > > I wouldn't have got this by myself without the explanation but if you > read the code as: > > typedef unsigned short uid_t; > > void dowork(uid_t u); > int main() { > int x = read_from_network(); > // Squish root (it's not safe to execute dowork() with uid 0) > if ( (x & 0x0000ffff) == 0) exit(1); > // ^^^^^^^^^^^^^ > dowork(x); > } > > you would have noticed the issue. > I get what he's saying but I just don't get it: why would the compiler convert from int to unsigned short *before* it has to send the value into the call to dowork()? E.g., 'x' should be an int until I (explicitly or implicitly) cast it to something else, non? Actually it should still be an int after the call to dowork(); it just won't be an int when dowork() gets it. Maybe I need to go back to school because I'm feeling very noobish right now.
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