Basically you're right. If it's not included, it's because no one pushed a change for inclusion. Wireshark includes as many protocols as possible and zookeeper would be definitively accepted. Before starting, be sure that something doesn't exist out there: you could start for someone else's code (according to its licence, of course) and not start from scratch. When submitting the dissector, please be sure to add sample captures for testing. To add them, just file a bug on bugzilla with your attachments, and add a reference "Bug: XXX" in your commit message that will automatically link the bugzilla page. Dario.
On Wed, Jan 24, 2018 at 9:12 AM, Jeff Widman <[email protected]> wrote: > How do I get a dissector for Zookeeper's protocol included by default in > Wireshark? > > I searched but couldn't find anything about what's required to "promote" a > dissector to be packaged with wireshark... > > I assume it's more than just code, that there's some process for deciding > whether a protocol is popular enough that a dissector for it could be > included in core. > > Zookeeper is an open-source database for reliably storing metadata. Many > popular open-source distributed systems rely heavily on it, including > Kafka, Hadoop, Druid, etc. > > Given this popularity, I suspect the only reason it's not bundled into > Wireshark is no one has had the time to write it, but wanted to confirm > before I start hacking on it. > > > -- > > *Jeff Widman* > jeffwidman.com <http://www.jeffwidman.com/> | 740-WIDMAN-J (943-6265) > <>< > > ____________________________________________________________ > _______________ > Sent via: Wireshark-dev mailing list <[email protected]> > Archives: https://www.wireshark.org/lists/wireshark-dev > Unsubscribe: https://www.wireshark.org/mailman/options/wireshark-dev > mailto:[email protected]?subject= > unsubscribe >
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