One way would be to transpose the array, delete rows 13,12,11,10,9 and 1,
then transpose the array back again.

DAve.

> -----Original Message-----
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED]]On Behalf Of Brian Mowers
> Sent: Thursday, May 09, 2002 3:41 PM
> To: Multiple recipients of list witango-talk
> Subject: Witango-Talk: Re: Making a 6 Column Array from a 13 column
> array.
>
>
>
> I can't seem to make this one work. I want to create a new 6 column array
> from a 13 column array in a results action.
> I also want to tack on a <@CRLF> at the end of the new array.
> Specifically I want columns 2,3,5,6,7,8  from the resultset array then I
> want to tack on an extra <@CRLF> at the end of it.
>
> Should be simple but this one is giving me fits.
>
> I don't splice and dice arrays, I usually work with
> <@column>,<@Col Num=n> etc.
> I have tried:
> <@assign local$vSixColumns Value='<@ARRAY ROWS=<@NumRows> COLS=6
> VALUE="@@MailArray[*,2] @@MailArray[*,3] @@MailArray[*,5]
> @@MailArray[*,6]
> @@MailArray[*,7] @@MailArray[*,8]"> <@CRLF>'>
>
>
> But all I get is a one column array.
>
> Best regards,
>
> Brian Mowers
>
>
> ________________________________________________________________________
> TO UNSUBSCRIBE: send a plain text/US ASCII email to [EMAIL PROTECTED]
>                 with unsubscribe witango-talk in the message body

________________________________________________________________________
TO UNSUBSCRIBE: send a plain text/US ASCII email to [EMAIL PROTECTED]
                with unsubscribe witango-talk in the message body

Reply via email to